This is another 100 watt
inverter circuit diagram. Built based on IC CD4047 and Mosfet IRF540,
this inverter have ability to supply electronic device -which require
220VAC- up to 100w from 2-3A transformer from 12V lead acid battery.
In the circuit diagram we can observe that 12V battery is connecter
to the diode LED and also connected to the pin8 of the IC 4047 which is
VCC or power supply pin and also to pin 4 and 5 which are astable and
complement astable of the IC. Diode in the circuit will help not give
any reverse current, LED will work as a indicator to the battery is
working or not.
IC CD4047 will work in the astable multivibrator mode. To work it in
astable multivibrator mode we need an external capacitor which should be
connected between the pin1 and pin3. Pin2 is connected by the resistor
and a variable resistor to change the change the output frequency of the
IC. Remaining pins are grounded .The pins 10 and 11 are connected to
the gate of the mosfets IRF540. The pin 10 and 11 are Q and ~Q from
these pins the output frequencies is generated with 50% duty cycle.
The output frequency is connected to the mosfets through resistor
which will help to prevent to the loading of the mosfets. The main AC
current is generated by the two mosfets which will act as a two
electronic switches. The battery current is made to flow upper half or
positive half of the primary coil of transformer through Q1 this is done
when the pin 10 becomes high and lower half or negative half is done by
opposite current flow through the primary coil of transformer, this is
done when pin 11 is high. By switching the two mosfets current is
This AC is given to the step up transformer of the secondary coil
from this coil only we will get the increased AC voltage , this AC
voltage is so high; from step up transformer we will get the max
voltage. Zenor diode will help avoid the reverse current.
Warning!: Lethal potential at the output of transformer, please be
careful, enclose this power inverter circuit into the plastic box.